Ammonia burns in the presence of a copper catalyst to form nitrogen gas. 4NH3(g) + 3O2(g)
Question:
4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(g);
∆H = –1267 kJ
What is the enthalpy change to burn 35.8 g of ammonia?
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The molar mass of ammonia is 1703 gmol From the equati...View the full answer
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