Find the absolute maximum and absolute minimum values of f on the given interval. 47. f(x) =
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47. f(x) = 3x? - 12x + 5. [0, 3] 48. f(x) = x - 3x + 1, [0, 3] 49. f(x) = 2x - 3x - 12x + 1. [-2, 3] 50. f(x) = x' – 6x² + 9.x + 2. [-1,4] 51. f(x) = x* - 2x² + 3, [-2, 3] 52. f(x) = (x - 1)'. [-1.2] 53. f(x) =T [0, 2] x* + x² - 4 x + 4' (-4.4] 54. f(x) [-4, 4] 55. f(1) = t4 - F. [-1,2] 56. f(1) = ī(8 – 1, [0. 8] 57. f(x) = sin x + cos x, [0, 7/3] 58. f(x) = x - 2 cos x, [-7, 7] 59. f(x) = xe". [0, 2] 60. f(x) = (In x)/x, [1. 3] %3D 61. f(x) = x - 3 In x. [1, 4] [0. 1] 62. f(x) = e* - e*
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47 fx 3x 12x 5 03 fx 6x120 x2 Applying the Closed Interval Method we find that f0 5 f2 7 and f3 4 So f0 5 is the absolute maximum value and f2 7 is th...View the full answer
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