Prove that by differentiating the integral. Verify, using calculus, that a = EX is indeed a minimum.
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by differentiating the integral. Verify, using calculus, that a = EX is indeed a minimum. List the assumptions about Fx and fx that are needed.
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2EX a Therefore if d daEXa 2 0 then 2EXa 0 which impli...View the full answer
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