Evaluate the surface integral. S y 2 dS is the part of the sphere x 2
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Evaluate the surface integral.
∫∫S y2dS is the part of the sphere x2 + y2 + z2 = 4 that lies inside the cylinder x2 + y2 = 1 and above the xy-plane
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To evaluate the surface integral S y2 dS over the part of the sphere x2 y2 z2 4 that lies inside the ...View the full answer
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