The maximum phase shift that can be obtained by using a lead compensator with transfer function (mathrm{G}(s)=frac{4(1+0.15
Question:
The maximum phase shift that can be obtained by using a lead compensator with transfer function \(\mathrm{G}(s)=\frac{4(1+0.15 s)}{(1+0.05 s)}\) is equal to
(a) \(15^{\circ}\)
(b) \(30^{\circ}\)
(c) \(45^{\circ}\)
(d) \(60^{\circ}\).
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