Ethyl alcohol and hexane form an azeotrope containing (33.2 mathrm{~mol}) per cent ethanol at (58.7^{circ} mathrm{C}) and
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Ethyl alcohol and hexane form an azeotrope containing \(33.2 \mathrm{~mol}\) per cent ethanol at \(58.7^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) pressure. Determine the van Laar parameters at this temperature. Assume the system to follow modified Raoult's law. The vapour pressures by Antoine equation are
\[ \ln P_{1}^{\text {Sat }}=16.6758-\frac{3674.49}{T+226.45} \]
and
\[ \ln P_{2}^{\text {Sat }}=13.8216-\frac{2697.55}{T+224.37} \]
where \(P\) is in \(\mathrm{kPa}\) and \(T\) in \({ }^{\circ} \mathrm{C}\).
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