A chemist put 1.18 mol of substance A and 2.85 mol of substance B into a 10.0-L
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A chemist put 1.18 mol of substance A and 2.85 mol of substance B into a 10.0-L flask, which she then closed. A and B react by the following equation:
A(g) + 2B(g) ⇌ 3C(g) + D(g)
She found that the equilibrium mixture at 25°C contained 0.376 mol of D. How many moles of B are in the flask at equilibrium at 25°C?
a. 2.47 mol
b. 3.60 mol
c. 2.52 mol
d. 2.10 mol
e. 2.41 mol
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From the chemical equation A 2 B 3 C D We can clearly state ...View the full answer
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