The wavenumber of the fundamental vibrational transition of 35 Cl 2 is 564.9 cm 1 . Calculate
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The wavenumber of the fundamental vibrational transition of 35Cl2 is 564.9 cm−1. Calculate the force constant of the bond (m(35Cl) = 34.9688 u).
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aa frequency c 1 2998x10 8 ms x 5469 cm 1 x100 cmm 1640x10 13 ...View the full answer
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