If a ball is thrown upward from the top of a building 128 ft high with an
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If a ball is thrown upward from the top of a building 128 ft high with an initial velocity of 16 ft/s, then the height h above the ground t seconds later will be
h = 128 + 16t - 16t2
During what time interval will the ball be at least 32 ft above the ground?
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The ball will be at least 32 ft above the ground if h 3...View the full answer
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