Suppose f(3) = 2, f '(3) = 1/2 , and f'(x) > 0 and f''(x), < 0
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Suppose f(3) = 2, f '(3) = 1/2 , and f'(x) > 0 and f''(x), < 0 for all x.
(a) Sketch a possible graph for f.
(b) How many solutions does the equation f (x) = 0 have? Why?
(c) Is it possible that f'(2) = 1/3? Why?
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