A block of weight w = 30.0 N sits on a frictionless inclined plane, which makes...
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A block of weight w = 30.0 N sits on a frictionless inclined plane, which makes an angle = 27.0° with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 13.6 N, applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed. 6 Part C What is WF, the work done on the block by the applied force as the block moves a distance L = 5.00 m up the incline? Express your answer numerically in joules. ▸ View Available Hint(s) Wp= ΜΕ ΑΣΦ ? J Submit Part D What is WN, the work done on the block by the normal force as the block moves a distance L = 5.00 m up the inclined plane? Express your answer numerically in joules. ▸ View Available Hint(s) WN= Submit ΑΣΦ ? J A block of weight w = 30.0 N sits on a frictionless inclined plane, which makes an angle = 27.0° with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 13.6 N, applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed. 6 Part C What is WF, the work done on the block by the applied force as the block moves a distance L = 5.00 m up the incline? Express your answer numerically in joules. ▸ View Available Hint(s) Wp= ΜΕ ΑΣΦ ? J Submit Part D What is WN, the work done on the block by the normal force as the block moves a distance L = 5.00 m up the inclined plane? Express your answer numerically in joules. ▸ View Available Hint(s) WN= Submit ΑΣΦ ? J
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Given Weight of the block W300N Applied force F136N Inclination angle 27 Distance moved L500m To find work done we need to understand the concept of w... View the full answer
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