A small object with mass mo and horizontal speed vo moving in the +x direction hits...
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A small object with mass mo and horizontal speed vo moving in the +x direction hits a vertical rod at point A (yo = 2Lo/3) above the point P. After collision the small object falls down with zero speed in horizontal direction. The rod of length Lo is hinged at point P. The mass of the rod, mr, is not distributed uniformly and its mass per length, A, varies as A = Ao(Lo + y). (g is the magnitude of the gravitational acceleration.) 6. What is the total mass of the rod in terms of Xo and Lo? (a) 3XL/4 (b) 3XL0/2 (c) 5XL/2 (d) 3XL/2 (e) 3XL/2 7. What is the moment of inertia of the rod, Ip, in terms of Ao and Lo relative to point P? (a) 3X2L/4 (b) 3XL/2 (c) 3XL8/2 (d) 5AOL/12 (e) 7XL/12 8. What is the angular frequency of the rod, w, in terms of mo, vo, Ao, and Lo just after the collision? 2 movo L 2 movo Lo 2 movo (c) 3 Ip 2 moLo 3 Ip 3 Ip 3 Ip horizontal, find the angular frequency of the rod, w2, in terms of Ip, 9, Ao ve Lo. 5 gAoL 3 Ip 5 go 3 Ip /u+ 5 Xo Lo 3 Ip 2 movi Lo (a) 3 Ip 9. When the rod becomes 5 gLo 3 Ip (a) w + V (b) (b) |w + (c) (d) /w + (e) (d) 5 go Lo 3 Ip mo (e) /w + vo P A X A small object with mass mo and horizontal speed vo moving in the +x direction hits a vertical rod at point A (yo = 2Lo/3) above the point P. After collision the small object falls down with zero speed in horizontal direction. The rod of length Lo is hinged at point P. The mass of the rod, mr, is not distributed uniformly and its mass per length, A, varies as A = Ao(Lo + y). (g is the magnitude of the gravitational acceleration.) 6. What is the total mass of the rod in terms of Xo and Lo? (a) 3XL/4 (b) 3XL0/2 (c) 5XL/2 (d) 3XL/2 (e) 3XL/2 7. What is the moment of inertia of the rod, Ip, in terms of Ao and Lo relative to point P? (a) 3X2L/4 (b) 3XL/2 (c) 3XL8/2 (d) 5AOL/12 (e) 7XL/12 8. What is the angular frequency of the rod, w, in terms of mo, vo, Ao, and Lo just after the collision? 2 movo L 2 movo Lo 2 movo (c) 3 Ip 2 moLo 3 Ip 3 Ip 3 Ip horizontal, find the angular frequency of the rod, w2, in terms of Ip, 9, Ao ve Lo. 5 gAoL 3 Ip 5 go 3 Ip /u+ 5 Xo Lo 3 Ip 2 movi Lo (a) 3 Ip 9. When the rod becomes 5 gLo 3 Ip (a) w + V (b) (b) |w + (c) (d) /w + (e) (d) 5 go Lo 3 Ip mo (e) /w + vo P A X
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6 The total mass of the rod can be found by integrating the mass per length function A oLo y over th... View the full answer
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