Disk Y of rotational inertia Iy about its center is held at rest above disk X...
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Disk Y of rotational inertia Iy about its center is held at rest above disk X of rotational inertia Ix about its center. Disk X rotates about its center with an angular velocity +w₁. Disk Y is slowly lowered onto disk X until both disks are in contact and travel together with a common angular velocity. A graph of disk X's angular acceleration a as a function of time is shown. Which of the following equations can a student use to verify that angular momentum is conserved in the situation? Justify your selection. Ixw₁ = (Ix + Iy) (w₁ +a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X plus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. A B с Ixw₁ = (IxIx) (w₁ +a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. Ixw₁ = (Ix + Iy) (W₁ - 5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. Ixw₁ = (IxIx) (w₁ - a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to t₁. Acceleration Angular of Disk X 0- -α1 -210- -α3- -α4 .910- -α6 0 t₁ t₂ Time t3 tA Disk Y of rotational inertia Iy about its center is held at rest above disk X of rotational inertia Ix about its center. Disk X rotates about its center with an angular velocity +w₁. Disk Y is slowly lowered onto disk X until both disks are in contact and travel together with a common angular velocity. A graph of disk X's angular acceleration a as a function of time is shown. Which of the following equations can a student use to verify that angular momentum is conserved in the situation? Justify your selection. Ixw₁ = (Ix + Iy) (w₁ +a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X plus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. A B с Ixw₁ = (IxIx) (w₁ +a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. Ixw₁ = (Ix + Iy) (W₁ - 5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to ₁. Ixw₁ = (IxIx) (w₁ - a5t₁), because the final velocity of the two-disk system is equal to the initial velocity of disk X minus the magnitude of the area bound by the curve and the horizontal axis from ₁ to t₁. Acceleration Angular of Disk X 0- -α1 -210- -α3- -α4 .910- -α6 0 t₁ t₂ Time t3 tA
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Related Book For
Vector Mechanics for Engineers Statics and Dynamics
ISBN: 978-0073212227
8th Edition
Authors: Ferdinand Beer, E. Russell Johnston, Jr., Elliot Eisenberg, William Clausen, David Mazurek, Phillip Cornwell
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