Consider a problem with two machines illustrated on the attached slide. The challenge is that there...
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Consider a problem with two machines illustrated on the attached slide. The challenge is that there is only limited space, up to 20 jobs, between stations 1 and 2. The desired throughput of 2.4 jobs/hr is not achieved. a. Set up VUT (2 stations) and diagnose this situation using VUT. b. Please suggest the most appropriate keizen improvement. Hints: 1. By keizen improvements we typically label improvements that you can accomplish without any capital investments. Thus, these would not be buying an additional or faster machine. 2. VUT does not limit inventory, but predicts how much inventory will build up. Since VUT calculator does not have any constraint on buffer sizes, a way to use VUT calculator is to observe what average inventory accumulates in an given buffer. Note, that usually the inventory in a buffer changes between the min(Inv) and max(Inv). Since min(Inv) is expected to be 0, and max(Inv) needs to be not more than 20, the average inventory would logically not exceed 10. If it exceeds, some blocking must take place. Thus, you should look for keizen improvements that result in average inventory in front of station 2 not exceeding 10 jobs. I = 2.4 / hr Ca = 1.0 M1 М2 20 to = 22 min co² = 1.0 to = 19 min co? = 0.25 mf = 48 hr %3D m; = 3.3 hr m, = 8 hr m, = 10 min %3D Situation: Buffer only fits 20 jobs in front of M2 Desired TH of 2.4/hr Actual TH = 2.0/hr Actual WIP= 45 jobs Consider a problem with two machines illustrated on the attached slide. The challenge is that there is only limited space, up to 20 jobs, between stations 1 and 2. The desired throughput of 2.4 jobs/hr is not achieved. a. Set up VUT (2 stations) and diagnose this situation using VUT. b. Please suggest the most appropriate keizen improvement. Hints: 1. By keizen improvements we typically label improvements that you can accomplish without any capital investments. Thus, these would not be buying an additional or faster machine. 2. VUT does not limit inventory, but predicts how much inventory will build up. Since VUT calculator does not have any constraint on buffer sizes, a way to use VUT calculator is to observe what average inventory accumulates in an given buffer. Note, that usually the inventory in a buffer changes between the min(Inv) and max(Inv). Since min(Inv) is expected to be 0, and max(Inv) needs to be not more than 20, the average inventory would logically not exceed 10. If it exceeds, some blocking must take place. Thus, you should look for keizen improvements that result in average inventory in front of station 2 not exceeding 10 jobs. I = 2.4 / hr Ca = 1.0 M1 М2 20 to = 22 min co² = 1.0 to = 19 min co? = 0.25 mf = 48 hr %3D m; = 3.3 hr m, = 8 hr m, = 10 min %3D Situation: Buffer only fits 20 jobs in front of M2 Desired TH of 2.4/hr Actual TH = 2.0/hr Actual WIP= 45 jobs
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