Mutt's utility function is U (m, j) = max {4m, j} and Jeff's utility function is...
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Mutt's utility function is U (m, j) = max {4m, j} and Jeff's utility function is U (m, j) = 3m+j. Mutt is initially endowed with 3 units of milk and 2 units of juice and Jeff is initially endowed with 5 units of milk and 6 units of juice. If we draw an Edgeworth box with milk on the horizontal axis and juice on the vertical axis and if we measure goods for Mutt by the distance from the lower left corner of the box, then the set of Pareto optimal allocations includes the: (a) left edge of the Edgeworth box, but no other edges. (b) bottom edge of the Edgeworth box, but no other edges. (c) left edge and bottom edge of the Edgeworth box. (d) right edge of the Edgeworth box, but no other edges. (e) right edge and top edge of the Edgeworth box. Mutt's utility function is U (m, j) = max {4m, j} and Jeff's utility function is U (m, j) = 3m+j. Mutt is initially endowed with 3 units of milk and 2 units of juice and Jeff is initially endowed with 5 units of milk and 6 units of juice. If we draw an Edgeworth box with milk on the horizontal axis and juice on the vertical axis and if we measure goods for Mutt by the distance from the lower left corner of the box, then the set of Pareto optimal allocations includes the: (a) left edge of the Edgeworth box, but no other edges. (b) bottom edge of the Edgeworth box, but no other edges. (c) left edge and bottom edge of the Edgeworth box. (d) right edge of the Edgeworth box, but no other edges. (e) right edge and top edge of the Edgeworth box.
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The correct answer is choice a on the proper fringe of the Edgeworth box and no different edges Pare... View the full answer
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