Problem 5. A certain town has 250,000 families, of which 25,000 do not have a TV...

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Problem 5. A certain town has 250,000 families, of which 25,000 do not have a TV at home. As part of an opinion survey, a simple random sample of 900 families is chosen. What is the chance that between 9% and 11% of the sample families will not have a TV at home? [This is a straightforward problem on the CLT for binomial distribution; the answer is P(|Z| < 1) 0.68] Problem 5. A certain town has 250,000 families, of which 25,000 do not have a TV at home. As part of an opinion survey, a simple random sample of 900 families is chosen. What is the chance that between 9% and 11% of the sample families will not have a TV at home? [This is a straightforward problem on the CLT for binomial distribution; the answer is P(|Z| < 1) 0.68]

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To solve this problem we can apply the Central Limit Theorem CLT to the binomial distribution The CL... View the full answer