Static Equilibrium 25 pts 4.1 Free body Diagram 5/5 -0 pts Correct 4.2 Tension Left Rope...

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Static Equilibrium 25 pts 4.1 Free body Diagram 5/5 -0 pts Correct 4.2 Tension Left Rope 3.5/6 -2.5 pts Missing vertical component of tension in the right rope 4.3 Tension Right Rope 3.5/6 -2.5 pts Missing vertical component in the left rope 4.4 Location of box 5/8 -3 pts Wrong sign for torque form plank QUESTION 5 s Short Answer 2/5 -3 pts Incorrect 4. A uniform plank (weight wp = 350.0 N, L = 2.20 m) is suspended from two massless ropes attached to its endpoints. When a box with weight w = 238.7 N is placed on the plank, the arrangement hangs in equilibrium such that the left rope makes an angle of 45.0 from the vertical and the right rope makes an angle of 30.0 from the vertical. (25) TRCOS45 588.7 =cos45= 8325475 4=22 CUST10545= a) Draw a free-body diagram for the system. (5) IOS4 Fr 1350 238.7 b) Find the tension in the left rope. W-350 Sum of vertical force = 0 T Cos-wp-W = 0 Ticos 45-350-238.7=0 W=350 W=238.7 c) Find the tension in the right rope. (6) TR Cos - W- W = 0 TR I 5887 C0536 .961.34 Answer Units 832.547 N Answer Units 961.343 N d) Find the location of the box (distance measured from the left end of the plank). (8) rfsint plank = Wp Sin (0) 2 Left ropes TL = XI sin plank box. Wp +x T 'Sint = (L-X) W Answer 0.63 Units : Bux = (L-x) 16. sint 22 (34) +x (83250) (-635-122-x+-2287 x=0.63 Sin45=(22-x)238.7 Static Equilibrium 25 pts 4.1 Free body Diagram 5/5 -0 pts Correct 4.2 Tension Left Rope 3.5/6 -2.5 pts Missing vertical component of tension in the right rope 4.3 Tension Right Rope 3.5/6 -2.5 pts Missing vertical component in the left rope 4.4 Location of box 5/8 -3 pts Wrong sign for torque form plank QUESTION 5 s Short Answer 2/5 -3 pts Incorrect 4. A uniform plank (weight wp = 350.0 N, L = 2.20 m) is suspended from two massless ropes attached to its endpoints. When a box with weight w = 238.7 N is placed on the plank, the arrangement hangs in equilibrium such that the left rope makes an angle of 45.0 from the vertical and the right rope makes an angle of 30.0 from the vertical. (25) TRCOS45 588.7 =cos45= 8325475 4=22 CUST10545= a) Draw a free-body diagram for the system. (5) IOS4 Fr 1350 238.7 b) Find the tension in the left rope. W-350 Sum of vertical force = 0 T Cos-wp-W = 0 Ticos 45-350-238.7=0 W=350 W=238.7 c) Find the tension in the right rope. (6) TR Cos - W- W = 0 TR I 5887 C0536 .961.34 Answer Units 832.547 N Answer Units 961.343 N d) Find the location of the box (distance measured from the left end of the plank). (8) rfsint plank = Wp Sin (0) 2 Left ropes TL = XI sin plank box. Wp +x T 'Sint = (L-X) W Answer 0.63 Units : Bux = (L-x) 16. sint 22 (34) +x (83250) (-635-122-x+-2287 x=0.63 Sin45=(22-x)238.7