Use the area concept (not a Riemann sum or antidifferentiation) to evaluate S (2x+1) dx. Show...
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Use the area concept (not a Riemann sum or antidifferentiation) to evaluate S (2x+1) dx. Show your work. Use the area concept (not a Riemann sum or antidifferentiation) to evaluate S (2x+1) dx. Show your work.
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To evaluate the integral of 22x 1 dx using the area concept we can ... View the full answer
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