Calculate the power dissipated in each inverter circuit in Figure P16.13 for the following input conditions:

(a) Inverter a: (i) \(v_{I}=0.5 \mathrm{~V}\), (ii) \(v_{I}=5 \mathrm{~V}\);

(b) Inverter b: (i) \(v_{I}=0.25 \mathrm{~V}\), (ii) \(v_{I}=4.3 \mathrm{~V}\);

(c) Inverter \(\mathrm{c}\) : (i) \(v_{I}=0.03 \mathrm{~V}\), (ii) \(v_{I}=5 \mathrm{~V}\).

Transcribed Image Text:

VDD=5V RD = 20 VDD = 5 V VTNL = 0.7 V K = 10 A/V VTN=1.5 V KD = 100 A/V VIND = 0.7 V KD = 100 A/V T VDD = 5 V VTNL=-2 V K = 10 / ID VIND=1V KD = 100 A/ (a) Figure P16.13 (b) (c)