Vapor-liquid equilibrium data in mole fractions for the system acetone-air-water at 1 atm (101.3 Pa) are as
Question:
Vapor-liquid equilibrium data in mole fractions for the system acetone-air-water at 1 atm (101.3 Pa) are as follows:
(a) Plot the data as (1) a graph of moles acetone per mole air versus moles acetone per mole water, (2) partial pressure of acetone versus g acetone per g water, and (3) y versus x.
(b) If 20 moles of gas containing 0.015 mole fraction acetone is brought into contact with 15 moles of water in an equilibrium stage, what would be the composition of the discharge streams? Solve graphically. For both parts, neglect partitioning of water andair.
0.004 0.008 0.014 0.017 0.019 0.020 y, acetone in air: x, acetone in water: 0.002 0.004 0.006 0.008 0.010 0.012
Step by Step Answer:
a Equilibrium data are given in acetone mole fractions y and x To convert to a...View the full answer
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In this video, the concept of pressure has been explained. The bottle is filled up with water, remove the pipe, and now you can see the clear flow of water from the holes due to liquid pressure.You can see that the second layer is holding the weight of the first layer and the third layer holding the weight of both upper layers, that’s why liquid flows out wider from the third as compared to the first two.At the first hole, water doesn’t roll along the walls; it flows out at an angle.At the second hole, you’ll see that the water flows out at a wider angle as compared to the first hole.At the third hole, we can see that the flow of water is much wider/greater than the other holes.This proves that the pressure at the bottom of the bottle is much more than the pressure at the top layers. P = ????gh
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