Given the following data: 2ClF(g) + O2(g) Cl2O(g) + F2O(g) H = 167.4 kJ 2ClF3(g) +
Question:
2ClF(g) + O2(g) → Cl2O(g) + F2O(g) ΔH = 167.4 kJ
2ClF3(g) + 2O2(g) → Cl2O(g) + 3F2O(g) ΔH = 341.4 kJ
2F2(g) + O2(g) → 2F2O(g) ΔH = –43.4 kJ
Calculate ΔH for the reaction ClF(g) + F2(g) → ClF3(g)
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ClF 12 O 2 12 Cl 2 O 12 F 2 O H 12 ...View the full answer
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