Set up, but do not evaluate, an integral that represents the length of the cur 37. x=t-r.
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37. x=t-r. y =, 1s1s 2 38. x = 1+ e. y =r. -3 <1 3 39. x=1 + cos t, y=1- sin t. 0 40. x= In t, y - i+ I. 1<1<5 < 2T
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2t2 so 37 tt y 2 1 t 2 dxdt 12t and dydt dxdt dydt 1 2t 2t...View the full answer
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Related Book For
Calculus Early Transcendentals
ISBN: 9781337613927
9th Edition
Authors: James Stewart, Daniel K. Clegg, Saleem Watson, Lothar Redlin
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