Show that = (+) b(n, p.j 1), b(n, p, j): n-j+
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For j ≥ 1. Use this fact to determine the value or values of j which give b (n, p, j) its greatest value: Consider the successive ratios as j increases.
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= ("+) b(n, p.j – 1), b(n, p, j): n-j+
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