A certain harmonic oscillator has a position given as a function of time by z = (0.150
Question:
z = (0.150 m)[sin (Ït)],
where
The value of the force constant k is 0.455 N m1 and the mass of the oscillator m is 0.544 kg. Find time average of the kinetic energy of the oscillator over 1.00 period of the oscillator. How does the time average compare with the maximum value of the kinetic energy?
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Step by Step Answer:
Let u 0915 s 1 t The time average is ...View the full answer
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