Let A and B be observables. Suppose the simultaneous eigenkets of A and B {|a, b} form
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Let A and B be observables. Suppose the simultaneous eigenkets of A and B {|a′, b′〉} form a complete orthonormal set of base kets. Can we always conclude that [A, B] = 0?
If your answer is yes, prove the assertion. If your answer is no, give a counterexample.
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No we cannot always conclude that A B 0 based on the fact that the simultaneous eigenkets of A and B ...View the full answer
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