Explain the direction of the chemical shifts for Fe(0), Fe(II), and Fe(III) in Figure 22.20. Fe 2p
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Fe 2p at normal emission Fe 2p32 Fe 2p12 Fe (0) Fe/MgO(001) Fe(0) Fe;OM9O(001) Fe(ll & II) Fe(ll) Fe(lI) y-Fe,O3/MgO(001) Fe(llI) "shake up" "shake up" a-Fe,Og/a-Al2Og (0001) Fe(llI) 740 730 720 710 700 Binding Energy/ev Photo emission intensity /arb. units
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As electrons are removed from Fe to form Fe 2 or Fe 3 ...View the full answer
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