3.) Given the in-line slider crank mechanism shown: 110 X-7.5 a.) Find the lengths of link...

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3.) Given the in-line slider crank mechanism shown: 110 X-7.5 a.) Find the lengths of link 2 and link 3. 15 2 - Sin (15) sin (55) 12=2.5 sin (55) 2 = 2.37 13 - Sin (110) sin (55) (13=8.6 7.5 b.) At -30%, what is distance x? 28508 = 5:030 LA-142.080 lx = 237+8.6-2 (2.37) 18.6 cos (142) 2.30 LB-7.92 c.) What is Xmax and Xmin? X=10.57 3.) Given the in-line slider crank mechanism shown: 110 X-7.5 a.) Find the lengths of link 2 and link 3. 15 2 - Sin (15) sin (55) 12=2.5 sin (55) 2 = 2.37 13 - Sin (110) sin (55) (13=8.6 7.5 b.) At -30%, what is distance x? 28508 = 5:030 LA-142.080 lx = 237+8.6-2 (2.37) 18.6 cos (142) 2.30 LB-7.92 c.) What is Xmax and Xmin? X=10.57