A 0.150 kg particle moves along an x axis according to x(t) = 13.00 + 2.00t

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A 0.150 kg particle moves along an x axis according to x(t) = – 13.00 + 2.00t + 4.00t2 – 3.00t3, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.40 s?

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Jan 08, 2011 02:33 AM

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A 0.150 kg particle moves along an x axis according to x(t) = 13.00 + 2.00t

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To solve the problem we note that acceleration is the secon...View the full answer

Fundamentals of Physics

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