A 10-cm length of wire carries a current of 2.0 A in the positive x direction. The
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A 10-cm length of wire carries a current of 2.0 A in the positive x direction. The force on this wire due to the presence of a magnetic field B is F = (3.0j + 2.0k) N. If this wire is now rotated so that the current flows in the positive y direction, the force on the wire is F = (–3.0i – 2.0k) N. Determine the magnetic field B.
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F 30 j 20 k N in terms of B 02 i B x i B y j B z k 3 j ...View the full answer
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