A 40.0-mH inductor, with internal resistance of 30.0 , is connected to an ac source (t) =
Question:
ℰ(t) = (286 V) sin [(390 rad/s)t]
(a) What is the impedance of the inductor in the circuit?
(b) What are the peak and rms voltages across the inductor (including the internal resistance)?
(c) What is the peak current in the circuit?
(d) What is the average power dissipated in the circuit?
(e) Write an expression for the current through the inductor as a function of time.
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a E t 286 Vsin390 rad st so 390 rad s Model the inductor a...View the full answer
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Related Book For 
Physics
ISBN: 978-0077339685
2nd edition
Authors: Alan Giambattista, Betty Richardson, Robert Richardson
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