A) A 75.0mL- volume of 0.200M NH3 (Kb= 1.8*10^-50 is titrated with 0.500HNO3. Calculate the pH after
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B) A 52.0mL- volume of 0.35M CH3COOH (Ka-1.8 * 10^-5) is titrated with 0.40M NaOH. Calculate the pH after the addition of 33.0mL of NaOH.
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A Initial moles of NH 3 751000 x 0200 0015 mol Moles of HNO 3 added 171000 x 050...View the full answer
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