A block of mass m on a horizontal table is attached to a spring of force constant
Question:
A block of mass m on a horizontal table is attached to a spring of force constant k as shown in Figure. The coefficient of kinetic friction between the block and the table is mk. The spring is stretched a distance A and released.
(a) Apply Newton’s second law to the block to obtain an equation for its acceleration d2x/dt2 for the first half-cycle, during which the block is moving to the left. Show that the resulting equation can be written d2x’/dt2 = - ώ2x’, where x = 0 at the equilibrium position of the spring, and x’ = x - x0, with x0 = μk mg/k = μk g/ώ 2.
(b) Repeat part (a) for the second half-cycle as the block moves to the right, and show that d2x’/dt2 = - ώ2x’’, where x’’= x + x0 and x0 has the same value.
(c) Sketch x(t) for the first few cycles for A = 10x0.
Step by Step Answer:
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry