A circumferential fin of rectangular cross section, 3.7 cm OD and 0.3 cm thick surrounds a 2.5

Question:

A circumferential fin of rectangular cross section, 3.7 cm OD and 0.3 cm thick surrounds a 2.5 cm diameter tube. The fin is constructed of mild steel. Air blowing over the fin produces a heat transfer coefficient of 28.4 W/(m2 K). If the temperatures of the base of the fin and the air are 260?C and 38?C, respectively, calculate the heat transfer rate from the fin.GIVENA mild steel circumferential fin of a rectangular cross section on a tubeTube diameter (Dt) = 2.5 cm = 0.025 mFin outside diameter (Df) = 3.7 cm = 0.037 mFin thickness (t) = 0.3 cm = 0.003 mHeat transfer coefficient ( hc ) = 28.4 W/(m2 K)Fin base temperature (Ts) = 260?CAir temperature (T??) = 38?CASSUMPTIONSThe system has reached steady stateThe mild steel is 1% carbon steelThe thermal conductivity of the steel is uniformRadial conduction only (temperature is uniform across the cross section of the fin)The heat transfer from the end of the fin can be accounted for by increasing the length by half the thickness and assuming the end isinsulated