A diverging lens (f = -10.0 cm) is located 20.0 cm to the left of a converging
Question:
(a) Determine the distance of the final image relative to the converging lens.
(b) What is the height of the final image (including the proper algebraic sign)?
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The following drawing shows the arrangement of the lenses and the location of the object The thinlens equation can be used to locate the final image p...View the full answer
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