A molybdenum (Z = 42) target is bombarded with 35.0 keV electrons and the x-ray spectrum of Fig. 40-13 results. The Kβ and Ka wavelengths are 63.0 and 71.0 pm, respectively. What photon energy corresponds to the
(a) Kβ
(b) Ka radiation? The two radiations are to be filtered through one of the substances in the following table such that the substance absorbs the Kβ line more strongly than the Ka line. A substance will absorb radiation x1 more strongly than it absorbs radiation x2 if a photon of x1 has enough energy to eject a Kelectron from an atom of the substance but a photon of x2 does not. The table gives the ionization energy of the K electron in molybdenum and four other substances. Which substance in the table will serve
(c) Best
(d) Second best as the filter?

Transcribed Image Text:

Zr Nb Mo Tc Ru Ll 40 40 42 43 Ex(keV) 18.00 18.99 20.00 21.04 22.12 nunious spectrum Kß 30 40 50 60 70 80 90 Wavelength (pm)