An electric field given by E = 4.0i 3.0(y2 + 2.0)j pierces a Gaussian cube of

Question:

An electric field given by E = 4.0i – 3.0(y2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown in Figure (The magnitude E is in Newton’s per coulomb and the position x is in meters.) What is the electric flux through the

(a) Top face,

(b) Bottom face,

(d) Back face?

(e) What is the net electric flux through the cube?