Consider the dissociation of 1 kmol of A2 through the elementary step A2 ↔ 2A. If ε stands for the degree of dissociation (fraction of 2 by volume that is dissociated), the overall reaction can be represented by A2 ↔ (1-ε)A2 + 2εA. At 500 K and 100 kPa, the equilibrium constant is calculated as 1.
(a) Determine ε.
(b) What would be the value of ε if the pressure is reduced to 0.01 kPa.
(c) What-if Scenario: Plot how the degree of dissociation changes as the pressure is increased from 0.01 MPa to 1 MPa.