A current-carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V/m.

Question:

A current-carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V/m. What are?
(a) The current carried by the wire;
(b) The potential difference between two points in the wire 6.4 m apart;
(c) The resistance of a 6.4-m length of this wire?