During a "brownout," which occurs when the power companies cannot keep up with high demand, the voltage of the household circuits drops below its normal 120 V.
(a) If the voltage drops to 108 V, what would be the power consumed by a "100-W" light bulb (that is, a light bulb that consumes 100.0 W when connected to 120 V)? Ignore (for now) changes in the resistance of the light bulb filament.
(b) More realistically, the light bulb filament will not be as hot as usual during the brownout. Does this make the power drop more or less than that you calculated in part (a)? Explain.