For the arrangement of forces in Problem 117, a 2.00 kg particle is released at x = 5.00 m with an initial velocity of 3.45 m/s in the negative direction of the x axis.(a) If the particle can reach x = 0 m, what is its speed there, and if it cannot, what is its turning point? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 5.00 m at speed 3.45 m/s.(b) If the particle can reach x = 13.0 m, what is its speed there, and if it cannot, what is its turningpoint?

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-x (m) 10 12