For the reaction at 298 K, 2NO2(g) N2O4(g) the values of Ho and So are 58 03 kJ and 176 6 J K, respectively What is the value of Go at 298 K Assuming that Ho and So do not depend on temperature, at what temperature is Go 0 Is Go negative above or below this temperature

Question: For the reaction at 298 K, 2NO2(g) N2O4(g) the values of Ho and So are 58.03 kJ and 176.6 J/ K, respectively. What is

For the reaction at 298 K, 2NO2(g) ⇌ N2O4(g) the values of ΔHo and ΔSo are –58.03 kJ and –176.6 J/ K, respectively. What is the value of ΔGo at 298 K? Assuming that ΔHo and ΔSo do not depend on temperature, at what temperature is ΔGo = 0? Is ΔGo negative above or below this temperature?

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