If f; g F(X) are increasing, then f + g is increasing f is
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• f + g is increasing
• αf is increasing for every α ≥ 0
Therefore the set of all increasing functionals on a set X is a cone in F(X).
Moreover, if f is strictly increasing, then
• f + g is strictly increasing
• αf is strictly increasing for every α > 0
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For every 2 1 2 1 2 1 Adding 2 2 2 1 1 1 That is is increasing Similarly for every 0 2 1 and there...View the full answer
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