In each case determine if X lies in U = span{Y, Z}. If X is in U,

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In each case determine if X lies in U = span{Y, Z}. If X is in U, write it as a linear combination of Y and Z; if X is not in U, show why not.
(a) X = [2 -1 0 1]T, Y=[l 0 0 1]T, and Z=[0 1 0 1]T.
(b) X = [l 2 15 U]T,Y=[2 -1 0 2]T, and Z= [1 -1 -3 1]T.
(c) X= [8 3 -13 20]T, K=[2 1 -3 5]T, and Z=[-l 0 2 -3]T.
(d) X= [2 5 8 3]T,Y=[2 -1 0 5]T, and Z = [-1 2 2 -3]T.
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