In Example 9-6 we described how the spring-like effect in a golf club could be determined by
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Club 1: 0.8406, 0.8104, 0.8234, 0.8198, 0.8235, 0.8562,
0.8123, 0.7976, 0.8184, 0.8265, 0.7773, 0.7871
Club 2: 0.8305, 0.7905, 0.8352, 0.8380, 0.8145, 0.8465,
0.8244, 0.8014, 0.8309, 0.8405, 0.8256, 0.8476
(a) Is there evidence that coefficient of restitution is approximately normally distributed? Is an assumption of equal variances justified?
(b) Test the hypothesis that both brands of ball have equal mean coefficient of restitution. Use a = 0.05.
(c) What is the P-value of the test statistic in part (b)?
(d) What is the power of the statistical test in part (b) to detect a true difference in mean coefficient of restitution of 0.2?
(e) What sample size would be required to detect a true difference in mean coefficient of restitution of 0.1 with power of approximately 0.8?
(f) Construct a 95% two-sided CI on the mean difference in coefficient of restitution between the two brands of golf clubs.
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Related Book For
An Introduction to Derivative Securities Financial Markets and Risk Management
ISBN: 978-0393913071
1st edition
Authors: Robert A. Jarrow, Arkadev Chatterjee
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