In Exercises 1-4, solve the equation algebraically. Round your result to three decimal places, if necessary. Verify
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1. 2x2e2x + 2xe2x = 0
2. −x2e−x + 2xe−x = 0
3. −xe−x + e−x = 0
4. e−2x − 2xe−2x = 0
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1 2x 2 e 2x 2xe 2x 0 2x 2 2xe 2x 0 2x 2 2x 0 because e 2x 0 2xx 1 0 x 0 1 2 x 2 ex 2xe x 0 x 2 ...View the full answer
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