Question: In Figure (a) a 2.0 N force is applied to a 4.0 kg block at a downward angle as the block moves rightward through

In Figure (a) a 2.0 N force is applied to a 4.0 kg block at a downward angle θ as the block moves rightward through 1.0 m across a frictionless floor. Find an expression for the speed vf of the block at the end of that distance if the block's initial velocity is

(a) 0 and

(b) 1.0 m/s to the right

(c) The situation in Figure (b) is similar in that the block is initially moving at 1.0 m/s to the right, but now the 2.0 N forces is directed downward to the left. Find an expression for the speed vf of the block at the end of the 1.0 m distance.

(d) Graph all three expressions for vf versus downward angle θ for θ = 0 to θ = 90o. Interpret the graphs.

(a) (b)

(a) (b)

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a Eq 710 along with Eq 71 and Eq 77 leads to v 2Fcose11 cose12 V where ... View full answer

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