In preparation for its tire rotation, a car weighing 2.25 tons is placed on a hydraulic garage
Question:
(a) Calculate the work done on the car when it is lifted.
(b) Assuming no frictional losses in the hydraulic fluid, how much work was done by the lift on the input side?
(c) What was the force on the input side if its piston moved 52.5 cm?
(d) Determine the ratio of the input side area to that of the lifting side (output) area?
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Step by Step Answer:
a Using 1 N 0225 lb from the front inside cover to convert units we have mg 225 tons ...View the full answer
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