In Section 2.8, the conjugate-symmetric and conjugate-antisymmetric components of a sequence x[n] were defined, respectively, as x
Question:
In Section 2.8, the conjugate-symmetric and conjugate-antisymmetric components of a sequence x[n] were defined, respectively, as
xe[n] = ½ (x[n] + x*[– n]).
X0[n] = ½ (x[n] – x*[– n]).
In Section 8.6.4, we found it convenient to respectively define the periodic conjugate symmetric and periodic conjugate-anti symmetric components of a sequence of finite duration N as
xep[n] = ½{x[((n))N] + x*[((– n))N]}, 0 ≤ n ≤ N – 1,
x0p[n] = ½ {x[((n))N] − x*[((– n))N]}, 0 ≤ n ≤ N – 1,
(a) Show that xep[n] can be related to xe[n] and that x0p[n] can be related to x0[n] by the relations
xep[n] = (xe[n] + xe[n – N]), 0 ≤ n ≤ N – 1,
x0p[n] = (x0[n] + x0[n – N]), 0 ≤ n ≤ N – 1.
(b) x[n] is considered to be a sequence of length N, and in general, xe[n] cannot be recovered from
Xep[n], and x0[n] cannot be recovered from x0p[n]. Show that with x[n] considered as a sequence of length N, but with x[n] = 0, n > N/2, xe[n] can be obtained from xep[n], and x0[n] can be obtained from xop[n].
Step by Step Answer:
Discrete Time Signal Processing
ISBN: 978-0137549207
2nd Edition
Authors: Alan V. Oppenheim, Rolan W. Schafer