In some applications the distribution of a discrete rv Xresembles the Poisson distribution except that zero is not a possible value of X. For example, let X = the number of tattoos t hat an individual wants removed when she or he arrives at a tattoo-removal facility. Suppose the pmf of X is

a. Determine the value of k.
b. If the mean value of X is 2.313035, what is the probability that an individual wants at most 5 tattoos removed?
c. Determine the standard deviation of X when the mean value is as given in (b).
[The article "An Exploratory Investigation of Identity Negotiation and Tattoo Removal" (Academy of Marketing Science Review, vol. 12, no. 6, 2008) gave a sample of 22 observations on the number of tattoos people wanted removed; estimates of µ and σ calculated from the data were 2.318182 and 1.249242, respectively.]

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p(x) = k x = 1, 2, 3, ..