In this example, there are G = 6 groups (cells). Assuming the die is fair, the probability

Question:

In this example, there are G = 6 groups (cells). Assuming the die is fair, the probability that a roll results in a 1 is p1 = 1/ 6, the probability that a roll results in a 2 is p2 = 1 / 6, etc. In goodness-of-fit tests, the expected values are found from some hypothesized distribution that determines the probability for each of the G groups.
In this case, we assume p1 = p2 = p3 = p4 = p5 = p6 = 1 / 6. The expected count for each of the 6 groups can be found from n × pi. Assuming all outcomes are equally likely, fill out the expected counts in Table 6.8.
Table 6.8 Observed and expected results of 30 rolls of a die.
In this example, there are G = 6 groups (cells).
Distribution
The word "distribution" has several meanings in the financial world, most of them pertaining to the payment of assets from a fund, account, or individual security to an investor or beneficiary. Retirement account distributions are among the most...
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: